Difference between revisions of "Bash operators"
From Linuxintro
imported>ThorstenStaerk |
imported>ThorstenStaerk |
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for i in $(seq 1 1 100); do echo $i; done | for i in $(seq 1 1 100); do echo $i; done | ||
| + | |||
| + | = $(()) = | ||
| + | The operator $(()) in the bash shell is replaced by the arithmetic result of the expression enclosed in the parentheses. | ||
| + | |||
| + | Examples: | ||
| + | # echo $((2*2)) | ||
| + | 4 | ||
Revision as of 13:58, 30 March 2009
$()
The operator $() in the bash shell is replaced by the output of the command enclosed in the parentheses. It is equivalent to backticks (``), but can be cascaded more easily.
Examples:
rpm -ql $(rpm -qa)
for i in $(seq 1 1 100); do echo $i; done
$(())
The operator $(()) in the bash shell is replaced by the arithmetic result of the expression enclosed in the parentheses.
Examples:
# echo $((2*2)) 4
